illy
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illerino if youre not into the whole brevity thing
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« Reply #45 on: October 19, 2007, 05:04:09 PM » |
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Here is a primer of means, medians and modes. Some of the statements in this thread seem to indicate that this is warranted I have a dataset that includes 2,2,2,5,8,11,12
Mean = 6
(2+2+2+5+8+11+12)/7 = 42/7 = 6
The mean is the mathematical average of all these numbers
Median = 5
2 2 2 5 8 11 12 ......^........
The median is the value of the case falling in the middle, In this case, out of 7 values, it is the 4th value (5), having three greater than it, and three less than it.
Mode = 2
2 2 2 5 8 11 12 ..^............
The mode is the single most frequently occurring number, (the peak of the curve).
BTW 5uperchicken, this dataset is positively skewed as well. Skewness is a quantitative value than can be calculated. It will have either a positive or negative value depending on which way the data is skewed.
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Ammunition spitting is him, is it, you listening Littering written, it\\'s in slippers, get the rebel in him Sticking it with sinners, sizzlin\\' rhythm, verbally hit him Did he did it, or did he didn\\'t, admit it - Rugged Man - Give it Up
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5uperChicken
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« Reply #46 on: October 19, 2007, 05:30:04 PM » |
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and if you have 300 million pieces of data to input? which method would you use? WHY???
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illy
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illerino if youre not into the whole brevity thing
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« Reply #47 on: October 19, 2007, 05:36:30 PM » |
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and if you have 300 million pieces of data to input? which method would you use? WHY???
This has been explained already.
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Ammunition spitting is him, is it, you listening Littering written, it\\'s in slippers, get the rebel in him Sticking it with sinners, sizzlin\\' rhythm, verbally hit him Did he did it, or did he didn\\'t, admit it - Rugged Man - Give it Up
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5uperChicken
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« Reply #48 on: October 19, 2007, 05:43:48 PM » |
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On what basis do you claim that the uppermost quintile was excluded from the data?
Using the median, as opposed to the mean as a measure of central tendency does not exclude data from the analysis. The top 20% is in fact counted when calculating the median, which is based on the 50% mark, and I think you're misunderstanding what a median is, it is not calculated by taking the average of whatever values someone sees fit from the dataset.
If you have some specific proof that values in the upper range were excluded from the presented dataset, I would like to see it. Here's my proof
every body makes 1 dollar in 1973...(100*1) 100 mean 1 / median 1 now incomes go up for 2005..(60*1 + 40*10) 460 mean 4.6 / median..........1 no change in income reported with a 400% increase in overall income...which is reflected in the average.
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5uperChicken
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« Reply #49 on: October 19, 2007, 05:44:16 PM » |
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and if you have 300 million pieces of data to input? which method would you use? WHY???
This has been explained already. humor me....
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illy
Hero Member
   
Karma: +106/-105
Posts: 1,069
illerino if youre not into the whole brevity thing
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« Reply #50 on: October 19, 2007, 06:19:07 PM » |
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and if you have 300 million pieces of data to input? which method would you use? WHY???
This has been explained already. humor me.... From the census bureau. Again. The distribution of wealth in the United States has a large positive skew, with relatively few households holding a large proportion of the wealth. For this type of distribution, the median is the preferred measure of central tendency because it is less sensitive than the average (mean) to extreme observations. The median is also considerably lower than the average, and provides a more accurate representation of the wealth and asset holdings of the typical household. For example, more households have a net worth near the median of $55,000 than near the average of $182,381.On what basis do you claim that the uppermost quintile was excluded from the data?
Using the median, as opposed to the mean as a measure of central tendency does not exclude data from the analysis. The top 20% is in fact counted when calculating the median, which is based on the 50% mark, and I think you're misunderstanding what a median is, it is not calculated by taking the average of whatever values someone sees fit from the dataset.
If you have some specific proof that values in the upper range were excluded from the presented dataset, I would like to see it. Here's my proof
every body makes 1 dollar in 1973...(100*1) 100 mean 1 / median 1 now incomes go up for 2005..(60*1 + 40*10) 460 mean 4.6 / median..........1 no change in income reported with a 400% increase in overall income...which is reflected in the average.
And? Where is data excluded? (btw, there would still be 100 people, 100, not 460 is what you would be dividing by)
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« Last Edit: October 19, 2007, 07:13:45 PM by illy »
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Ammunition spitting is him, is it, you listening Littering written, it\\'s in slippers, get the rebel in him Sticking it with sinners, sizzlin\\' rhythm, verbally hit him Did he did it, or did he didn\\'t, admit it - Rugged Man - Give it Up
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5uperChicken
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« Reply #51 on: October 19, 2007, 07:20:21 PM » |
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and if you have 300 million pieces of data to input? which method would you use? WHY???
This has been explained already. humor me.... From the census burea. Again. The distribution of wealth in the United States has a large positive skew, with relatively few households holding a large proportion of the wealth. For this type of distribution, the median is the preferred measure of central tendency because it is less sensitive than the average (mean) to extreme observations. The median is also considerably lower than the average, and provides a more accurate representation of the wealth and asset holdings of the typical household. For example, more households have a net worth near the median of $55,000 than near the average of $182,381.Try repeating that part to yourself a few thousand times.If you have some specific proof that values in the upper range were excluded from the presented dataset, I would like to see it.[/b] Here's my proof every body makes 1 dollar in 1973...(100*1) 100 mean 1 / median 1 now incomes go up for 2005..(60*1 + 40*10) 460 mean 4.6 / median..........1 no change in income reported with a 400% increase in overall income...which is reflected in the average. And?
Where is data excluded? (btw, there would still be 100 people, 100, not 460 is what you would be dividing by) [/quote] Here's my proof
every body makes 1 dollar in 1973...(100*1) 100 mean 1 / median 1 now incomes go up for 2005..(60*1 + 40*10) 460 mean 4.6 / median..........1 no change in income reported with a 400% increase in overall income...which is reflected in the average.
[/quote]
And?
Where is data excluded? (btw, there would still be 100 people, 100, not 460 is what you would be dividing by) [/quote]The difference in the the median and average will tell you exactly what data was excluded.....a 460% increase in total income is not realized at all by the median. oh...by the way...60 plus 40 people IS 100 people...and when you divide 460 among those 100 people you get 4.6......not 1!
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« Last Edit: October 19, 2007, 07:22:23 PM by 5uperChicken »
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illy
Hero Member
   
Karma: +106/-105
Posts: 1,069
illerino if youre not into the whole brevity thing
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« Reply #52 on: October 19, 2007, 07:50:16 PM » |
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Whatever.
If you had actually read mt post, you would see where I told you that there were still 100 people.
Go and find me something beside your opinion if you want to make a convincing argument. With all due respect, you just don't stack up against the Census Bureau when it comes to authority or consensus regarding statistical methods for census data.
Yes, the median is less sensitive to highly skewed data (like income data). Just bolding one part of the quote and disregarding the rest really isn't convincing at all.
You accused a poster of dishonesty for using the same measures when reporting census data that the census bureau does. All logic and firmly established mathematical principles in the world aren't sufficient against your opinions.
First you claim the median is a dishonest meaure. I show where it isn't with a substantial explanation from the US Census Bureau. Then you take issue with the explanation because you think it's negatively skewed, I showed where it isn't. Then You make wild claims using the median to exclude data without showing what values you're talking about, and claiming the median is an average of only part of the data. I show where neither is the case.
Now, you want to interpret the census bureaus explanation for the convention to to mean the exact opposite of what it says.
Whatever.
I'm done with this "debate".
Typically, I charge by the hour for teaching math. Consider the schooling on central tendencies a freebie. I had it ready to go for the remedial math class I teach.
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« Last Edit: October 19, 2007, 08:14:52 PM by illy »
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Ammunition spitting is him, is it, you listening Littering written, it\\'s in slippers, get the rebel in him Sticking it with sinners, sizzlin\\' rhythm, verbally hit him Did he did it, or did he didn\\'t, admit it - Rugged Man - Give it Up
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5uperChicken
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« Reply #53 on: October 19, 2007, 07:59:14 PM » |
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Forever...
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Opmod
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« Reply #54 on: October 22, 2007, 05:15:28 PM » |
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Typically, I charge by the hour for teaching math. Consider the schooling on central tendencies a freebie. I had it ready to go for the remedial math class I teach.
OHH, good insult. Applauded
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\\\"Something witty\\\" Some self impotant blowhard
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